Question

a 50 microfarad capacitor in a defibrillator is charged to 3000v. the energy stored in the capacitor is sent through the victim during a pulse of duration 2 ms. the power of the pulse is close to?

Answer 1

Hii friend,

# Answer- 112.5kW

# Given-

C = 50 microfarad = 50×10^-6 farad

V = 3000 V

t = 2 ms = 2×10^-3 s

# Formula-

Power of the pulse is given by,

Power = 1/2 CV^2 / t

Power = (1/2×50×10^-6×3000^2)/(2×10^-3)

Power = 112500 W

Power = 112.5 kW

Power of the pulse is close to 112kW.

Thanks for asking...