Question

A 50 ml solution of strong acid of pH = 1 is mixed with a 50 ml solution of strong acid of pH = 2. The pH of the mixture will be nearly? (log 5.5 = 0.74)

Answer 1

Answer:

Answer : The pH of resulting solution is, 1.26

Solution :

First we have to calculate the concentration from the pH = 1 and pH = 2

concentration at pH = 1

concentration at pH = 2

and are the concentrations.

Now we have to calculate the concentration of resulting solution.

Formula used :

where,

and are the concentrations

is the concentration of resulting solution

and are the volume = 50 ml = 0.05 L

is the volume of resulting solution = 50 + 50 = 100 ml  = 0.1 L

Now put all the given values in the above formula, we get the concentration of resulting solution.

The concentration of the resulting solution =

Now we have to calculate the pH of the resulting solution.

Therefore, the pH of resulting solution is, 1.26

Read more on Brainly.in - https://brainly.in/question/2069988#readmore