Question

A 50 ml solution of strong acid of ph =1 is mixed with a 50ml solution of strong acid of ph=2 . The ph of the mixture will be nearly??

Answer 1

for acid with ph= 1,

[h+]= 10^-1

for acid with ph =2,

[h+]= 10^-2

now for mixture total gram euivalents will be same, so,

[h+]mix *volume of mixture= [h+]0f first acid*its volume+ [h+] of second acid*its volume

[h+]mix* 100 =10^-1*50+10^-2*50

[h+]mix= 5.5*10^-2

ph of mixture= -log[h+]

                       =-log[5.5*10^-2]

                        =1.26

Answer 2

hope it will help u and plzz mark as brainliest