Question

a) 50 ms-2
b) 100 ms-2
c) 150 ms-2
d) 200 ms
If a particle starting from rest is moving with a uniform acceleration of 10 ms-2, then the final
velocity when it covers a distance of 2 km is
a) 0.2 kms-1
b) 0.3 kms-2
c) 2 kms-2
d) 20 kms-2​

Answer 1

Answer:

v=0.2km/s

Explanation:

we are given

a=10m/s^2

u=0 m/s

v=?

s=2km=2000m

relation:-

v^2 - u^2 = 2as

v^2 = u^2+2as

v^2 = 0^2 + 2(10)(2000)

v^2 = 40000

v=200m/s

Now convert it into km/s

i.e.; 1000m/s--------> 1km/s

200m/s -------------> 200/1000 km/s

i.e.

v=0.2 km/s

Thankyou for reading.