Question

A 50 v battery is connected across a 10 ohm resistor the current is 4.5A the internal resistance of battery is

Answer 1

E=v+iR
=50+4.5*10
=95
internal resistance r=R(E/v-1)
=4.5(95/50-1)
=4.05

Answer 2

50=4.5(10+r)

Here we have to multiply 4.5 with the no in brackets4.5(10+r) and write it down seperately

So it becomes now,

4.5r=50-45=5

r=5/4.5=50/45=10/9=1.1 ohm