Question

A 500.0Hz sound source is moving away from an observer and approaching a wall at a speed of 20m/s. What is the frequency distinguished by the observer of the sound waves reaching him after reflecting on the wall? (Speed of sound on air: 335 m/s)

Answer 1

Answer:

Frequency observed by the observer is 563.5 Hz

Explanation:

Frequency of the reflected sound is given as

$f_{ap} = \frac{v + v_o}{v - v_o} f_o$

here we know that

$f_o = 500 Hz$

$v_o = 20 m/s$

$v = 335 m/s$

now from above formula we know

$f_{ap} = \frac{335 + 20}{335 - 20} 500$

$f_{ap} = 563.5 Hz$

#Learn

Topic : Doppler's Effect

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Answer 2

The apparent frequency is 563.4 Hz.

Explanation:

Given that,

Frequency of sound source= 500 Hz

Observer speed = 20 m/s

We need to calculate the apparent frequency

Using formula of frequency

$f=f_{o}(\dfrac{v+v_{0}}{v-v_{0}})$

Where, v = speed of sound

$v_{0}$ = observe speed

f = sound frequency

Put the value in to the formula

$f=500\times(\dfrac{335+20}{335-20})$

$f=563.4\ Hz$

Hence, The apparent frequency is 563.4 Hz.

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Topic : frequency

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