Question

A 500 kg body change its velocity from 20 meter persecond to 50 meter persecond in 3seconds what is the net force acting on the body?

Answer 1

Answer:

5000 N

Explanation:

As per the provided information in the given question, we have :

• Mass of the body (m) = 500 kg

• Initial velocity (u) = 20 m/s

• Final velocity (v) = 50 m/s

• Time taken (t) = 3 s

We've been asked to calculate the net force acting on the body.

The formula which is used to calculate the net force is,

$\qquad \qquad\sf{ \Bigg [ F = ma \Bigg ]}$

• F denotes Force
• m denotes mass
• a denotes acceleration

So, in order to calculate the Force, firstly we need to calculate the acceleration.

Acceleration is the rate of change in velocity or the change in velocity by time.

$\qquad \qquad\sf{ \Bigg [ a = \dfrac{v-u}{t}\Bigg ]}$

• a denotes acceleration
• v denotes final velocity
• u denotes initial velocity
• t denotes time

$\longrightarrow\sf{a = \dfrac{50 - 20}{3} \; ms^{-2}}$

$\longrightarrow\sf{a = \dfrac{30}{3} \; ms^{-2}}$

$\longrightarrow\boxed{\sf{a = 10 \; ms^{-2}}}$ … ( 1 )

Now, substitute the values in the formula to calculate net force.

$\qquad \qquad\sf{ \Bigg [ F = ma \Bigg ]}$

$\longrightarrow\sf{F = 500 \; kg \times 10 \; ms^{-2}}$

$\longrightarrow\sf{F = 5000 \; kg.ms^{-2}}$

$\longrightarrow\underline{\boxed{\sf{F = 5000 \; N} }}$

Therefore, the net force acting on the body is 5000 N.

$\rule{200}2$

Answer 2

$\bf \bigstar\underline{\: Information \: provided \: with \: us }$

$\rm \star (m)\: Mass \: of \: the \: body = 500 \: kg$

$\rm \star \: (u) \: Initial \: velocity \: of \: the \: body = 20 \: m/s$

$\rm \star \: (v) \: Final\: velocity \: of \: the \: body = 50 \: m/s$

$\rm \star \: (t) \: Time = 3 \: second$

$\bf \bigstar\underline{\: What \: we \: have \: to \: calculate } :$

$\rm \star \: (F)The \: net \: force \: \: acting \: on \: the \: body$

$\bf \bigstar\underline{\: We\: know \: that} :$

$\rm \implies \: Acceleration = \dfrac{Final \: velocity - Initial \: velocity}{Time}$

$\rm \implies \: Acceleration = \dfrac{v- u}{t}$

$\rm \implies \: Acceleration = \dfrac{50 - 20}{3}$

$\rm \implies \: Acceleration = \dfrac{50- 20}{3}$

$\rm \implies \: Acceleration = \dfrac{30}{3}$

$\rm \implies \: Acceleration = 10 \: m/ {s}^{2}$

$\bf \bigstar\underline{\: Now} :$

$\rm \implies \: Force = Mass \times Acceleration$

$\rm \implies \: Force = 500 \times 10$

$\rm \implies \: Force = 5,000 \: Newton$

$\bf \bigstar\underline{\: Therefore} :$

$\rm \therefore The \: force \: acting \: on \: the \: body \: is \: 5,000 \: N$

$\bf \bigstar \: \underline{Learn - more }$

• The net force means force acting on an object which is the combination of all of the individual forces acting on and it is the vector sum of all the forces that act upon an object and it can calculated using Newton's second law, in which states that F = ma, where: F is the net force. m is the mass of the object