Question

a 500 kg rocket has to be fired vertically exhaust velocity of gases is 1.96 kilometre per second minimum mass of the fuel to be released in KG per sec​

Answer 1

Explanation:

we know that m=500kg

v=1.96

f=ma

so

f=v(dm/dt)

f/v= (dm/dt)

mg/v=(dm/dt)

500*9.8/1.96

500*9.8/1.96*100. [9.8m/s^2=9.8/1000km/sec]

[dm/dt]=2.5 kg

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Answer 2

Answer:

25.51kg/s is the required answer.

Explanation:

Given:

Mass of the rocket(m)=500kg

Velocity=1.96km/s=1.96*100m/s

To find: Minimum mass of the fuel to be released in KG per sec​(dm/dt)

Solution:

We know that,

F=ma

∴F= m(dv/dt).   (∵a=dv/dt)

∴F/v=dm/dt

∴mg/v=dm/dt.   (∵F=mg)

∴dm/dt=500*10/1.96*100.   (g=10m/s²)

∴dm/dt=25.51kg/s

Therefore, 25.51kg/s is the required answer.