A 500 kg rocket has to be fired vertically. Exhaust velocity of the gases is 1.96 km/s. Minimum mass of fuel to be released in kg per second is?
Answers
Answered by
4
Force required to overcome the weight
F=mg=vdmdt
F
=
m
g
=
v
d
m
d
t
dmdt=mgv
d
m
d
t
=
m
g
v
=600×9.81000
=
600
×
9.8
1000
=5.88kg/s
=
5.88
k
g
/
s
Hence a is the correct answer.
answered Jul 14, 2013 by meena.p
edited May 27, 2014 by lmohan717
F=mg=vdmdt
F
=
m
g
=
v
d
m
d
t
dmdt=mgv
d
m
d
t
=
m
g
v
=600×9.81000
=
600
×
9.8
1000
=5.88kg/s
=
5.88
k
g
/
s
Hence a is the correct answer.
answered Jul 14, 2013 by meena.p
edited May 27, 2014 by lmohan717
Mayur358:
but the answer didn't match with the answers a)250kg b)25kg c)2.5kg d)50kg
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