A 500 kg satellite revolves around the earth at a height of 10³ km above the earth's surface. Calculate, assuming circular orbit : (i) speed of satellite, (ii) angular velocity of satellite, (iii) gravitational force of the earth on the satellite. Given : radius of the earth 6.4 x 10⁶ m, g = 9.80 ms⁻².
Ans. (i) 7.36 x 10³ ms⁻¹ , (ii) 9.95 x 10⁻⁴ rad s⁻¹ , (iii) 3.66 x 10³ N
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Answer:
(i) 7.36 x 10³ m/s (ii) 9.95 x 10⁻⁴ rad/s (iii) 3.66 x 10³ N
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