Physics, asked by Anonymous, 3 days ago

A 500-kg space-probe hits an asteroid of mass 1010 kg and. The probe was moving at 2 m/s before the collision and it bounced off the surface of the asteroid at 0.5 m/s after the collision. How much did the veloc- ity of the asteroid change due to this collision?

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Answered by b22554113

Answer:

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Explanation:

This is equal to the impact energy. For example, consider an asteroid that is one kilometer in diameter and weighs 1.4 billion tonnes (M = 1.4×1012 kilograms), and is traveling at 20 kilometers per second (V = 20,000 m/s). The kinetic energy would be equal to (1/2)×1.4×1012×(20,000)2 = 2.8×1020 Joules.

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A 500-kg space-probe hits an asteroid of mass 1010 kg and. The probe was moving at 2 m/s before the collision and it bounced off the surface of the asteroid at 0.5 m/s after the collision. How much did the veloc- ity of the asteroid change due to this collision?​

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A 500-kg space-probe hits an asteroid of mass 1010 kg and. The probe was moving at 2 m/s before the collision and it bounced off the surface of the asteroid at 0.5 m/s after the collision. How much did the veloc- ity of the asteroid change due to this collision?