A 500 kg truck moving at 20m/s experiences a force of 2000N due to brakes in opposite direction, until
the truck stops. Find the truck's:
i. Deacceleration
ii. Time Taken to stop
Answers
Answer:
m = 3000 kg
Explanation:
- Therefore, the mass of the car is 3000 kg.
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Explanation:
Mass of truck (m) = 500 kg
initial velocity of truck (u) = 20 m/s
force applied on the truck in direction of motion
(F) = -2000 N.
(since the force is acting in opposite direction of motion)
hence
acceleration of truck (a) = -2000 / 500 = -4 m/s
( since acceleration = force / mass)
( i ) deacceleration = 4 m/s^(-2)
( ii )
We know that,
final velocity of truck = 0 m/s
hence from the formula:
v = u + at
t = ( v - u ) / a. ( here a is acceleration)
therefore,
t = ( 0 - 20 ) / ( -4 ) = 5 s
hence,
time taken = 5 s
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