Question

A 500 kg vehicle moving with a speed of 10m/s is brought to rest at a distance of 25m. (2) a) Find the acceleration of the vehicle. b) Calculate the unbalanced force acting on it.

Answer 1

Answer:

given :-

mass of the vehicle = 500kg

v = 0

u = 10m/s

s = 50m

by third equation of motion, we get

→ 2as = v² - u²

→ 2 × a × 50 = 0 - 10²

→ 100a = -100

→ a = -100/100

→ a = -1 …(1)

we also know that a = (v - u)/t …(2)

by equation (1) and (2)

=> -1 = (0 - 10)/t

=> -1t = -10

=> t = -10/-1

=> t = 10

heny, acceleration is -1m/s^2 and time is 10 seconds

Explanation:

Hope it helps