Question

A 500-kilogram sports car accelerates uniformly from rest, reaching a speed of 30 meters per second in 6
seconds. During the 6 seconds, the car has traveled a distance of
(A) 15 m (B) 30 m (C) 60 m (D) 90 m (E) 180 m

Answer 1

Mass m = 500kg

Initial velocity ,u = 0

Final velocity ,v = 30 m/s

Time , t = 6s

So, acceleration , a =?

By using first equation of motion = v= u+at

= 30 = 0+ a ×6

=30 = 0+6a

=6a = 30 = a = 30/6 = a = 5m/s^2

So, distance travelled = s= ?

By using second equation of motion = s = ut+ 1/2 at^2

= s = 0× 6+1/2×5×6×6

s = 0+90

s= 90 m

Option d is correct = 90m

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