A 500 ml sample of a gas weights 0.326 g at 100 °C and 0.500 atm. What is the molecular mass of the gas
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PV = nRT
as n= Given mass (m) / Molar mass (M)
therefore PV= mRT/M
putting the values
0.500*500=0.326*373*0.083/M
M = 0.326*373*0.083/250
M= 0.386*1.492*0.083
M= AL {0.5132+0.1738+ 0.9191}
M = AL (1.6061)
M = 40.37
as n= Given mass (m) / Molar mass (M)
therefore PV= mRT/M
putting the values
0.500*500=0.326*373*0.083/M
M = 0.326*373*0.083/250
M= 0.386*1.492*0.083
M= AL {0.5132+0.1738+ 0.9191}
M = AL (1.6061)
M = 40.37
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14
hlw mate here is ur ans
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