A 500 watt bulb is placed at the centre of a perfectly black sphere of radius r is equal to 1 the approximate force experienced by the walls of the spear as it absorbs all the photon emitted by the bulb is what
Answers
The force experienced by the walls of the spear as it absorbs all the photon emitted by the bulb is F = 166.66 × 10^−8 N
Explanation:
Given data:
- Power of bulb "W" = 500 Watt
- Pressure = I / c = power / area × c
F / area = Power / area × c
F = Power / c = 500 / 3×10^8
F = 166.66 × 10^−8 N
Hence the force experienced by the walls of the spear as it absorbs all the photon emitted by the bulb is F = 166.66 × 10^−8 N.
Also learn more
(i)A glass flask having mass 309 g and as interior volume of 500 cm^3 floats on water,when it is less than half filled with water.the density of material of flask is
(ii)A open U tube contains Hg When 11.2 cm of water is poured into one of ams of the tube,how high does the Hg rise in other arm from its initial level
(iii)A beaker of water is palced on platform of spring balance .The balance reads 1.5 kg.a stone of mass 0.5 kg and d 500 kg./m^3 is immersed in water without touching the walls of the beaker.What will the balance read?
https://brainly.in/question/64734