Question

A 500cm^3solution is prepared by dissolving 2 g of Ca(OH)2 in water. Calculate the normality of the solution
(1)
27x10^-4
(2)
1.35*10^-3
(3)
27 * 10^-2
(4)
5.4 x 10^-2​

Answer 1

Explanation:

Mass of solute Ca(OH)2 (w) = 2 g

Molar Mass of solute (M) = 74 g

Volume of solution (V) = 500 cm³ = 500 ml = 0.5 L

• Normality (N) = Gram equivalent / Volume

Gram equivalent (eq) = given mass /equivalent weight

equivalent weight = molar mass /Valency factor

equivalent weight = 74 / 2 = 37

• eq = 2 / 37 = 0.054
• N = eq / V
• N = 0.054 / 0.5
• N = 0.108 N