Question

A 500g cube of lead is heated from 35 to 75 °C . Specific heat 0.139 J/g°C

Answer 1

Answer:

2780 joule

Explanation:

heat required for heating is given by

Q = m * c* t

where m is mass

c is specific heat and

t is change in temperature

therefore heat Q = 500 x 0.139 x (75-35)

= 2780 joule

Answer 2

Answer:

2780J

Explanation:

Mass x specific heat capacity x temp change

500 x 0.139 x 40

2780J