A 500g stone falls from a height of 2m .calculate what will be its kinetic energy just before touching the ground ,g =9.8m\s^2 ?
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Answered by
20
K.E.=mgh
m=500g=1/2kg
g=9.8
h=2m
∴K.E=(1/2)*9.8*2
=9.8 j
m=500g=1/2kg
g=9.8
h=2m
∴K.E=(1/2)*9.8*2
=9.8 j
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Answered by
13
given,
mass = 500 gram = 500/1000 = 1/2 = 0.5 kg
height = 2 meter
acceleration due to gravity = 9.8 m/s²
kinetic energy = mgh
K.E = 0.5 * 9.8 * 2
K.E = 9.8
therefore kinetic energy of the object is = 9.8 J
i hope it helps..............................^_^
mass = 500 gram = 500/1000 = 1/2 = 0.5 kg
height = 2 meter
acceleration due to gravity = 9.8 m/s²
kinetic energy = mgh
K.E = 0.5 * 9.8 * 2
K.E = 9.8
therefore kinetic energy of the object is = 9.8 J
i hope it helps..............................^_^
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