Question

A 500g stone is thrown up with a velocity of 15 m/s find it P.E at its maximum height
K.E when it hits the ground​

Answer 1

Answer:

Hence K.E=56.25J

Explanation:

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Answer 2

Answer:

i) PE at its maximum height is 112.5 J

ii) KE when it hits the ground is 112.5 J

Explanation:

Given:

• Mass (m) = 500g = 500 × 10⁻³ kg

• Velocity (v) = 15 m/s

To Find:

i) PE at its maximum height is 112.5 J

ii) KE when it hits the ground is 112.5 J

Solution:

According to the condition,

Here, Potential energy = kinetic energy (PE = KE)

=> 1/2 mv²

=> 1/2 × 500 × 10⁻³ kg × (15)²

=> 1/2 × 500 × 10⁻³ × 15 × 15

=> 500×15×15/2×1000

=> 500×225/1000

=> 225/2

=> 112.5 J

Hence, Both PE and KE is 112.5 Joules.