Question

A 500g tooth paste sample has 0.2gm fluoride concentration . what is the concentration of fluorine in terms of ppm level

Answer 1

Ppm= weight of solute/weight of sloution×10^6

= .2×10^6÷500= 400ppm

Answer 2

Answer:

The concentration of fluorine is determined to be equal to 400ppm in terms of ppm level.

Explanation:

Given that weight of tooth paste $= 500grams$

and weight of fluoride in it$= 0.2grams$

Here Concentration in ppm level is given by  $=(\frac{W_{C}}{W_{S}} )*10^{6}$

$W_{C}$  is weight of the constituent in the sample

$W_{S}$  is Weight of the  whole sample

Concentration in ppm level $=\frac{0.2}{500}*10^{6}=400ppm$