Physics, asked by delisha211bhasin, 6 months ago

) A 500kg vehicle moving with the speed of 10m/s is brought to rest in a distance of 20m find acceleration

Answers

Answered by harshapilla0000

1

Answer:

-2.5 m/sec^2

Explanation:

V^2 - U^2 = 2aS

0^2 - 100 = 2a(20)

-100= 40a

a= -2.5 m/sec^2.

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