Question

A 500W electric heater is designed to work with a 115V line.If the voltage of the line drops to110V,then what will be the percentage loss of energy liberated

Answer 1

Answer:

8.5%

Explanation:

Given  

A 500 W electric heater is designed to work with a 115 V line.If the voltage of the line drops to 110 V,then what will be the percentage loss of energy

Now power dissipated in external resistance will be

    P = (E / R + r)^2 R

   P1 = v1^2 / R = (115)^2 / R

  P2 = v2^2 / R = (!10)^2 / R

 Now change will be P1 – P2 / P1

                           = 115^2 – 110^2 / R / 115^2 / R

                      = (115 + 110)(115 – 110) / 115^2

                     = 1125 / 13,225

                 = 0.0850 x 100

               = 8.5%

So percentage loss of energy liberated will be 8.5%

Answer 2

Answer:

hey mate

ur ans is

Explanation:

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