Biology, asked by Anonymous, 11 months ago

A 50cm long wire of mass 20g support a mass of 1.6kg . find the fundamental frequency of the portion of the string between the wall and the pulley. (taking g=10ms)​

Answers

Answered by Anonymous
17

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★ the tension in the string is F,

 =  > (1.6) \times (10ms)

 =  > 16n

the linear mass density is,

 =  >  \frac{20g}{50cm}

 =  > 0.04kg \: m

and the fundamental frequency is,

v =  \frac{1}{2l}  \sqrt{ \frac{f}{u} }

 =  >  \frac{1}{2 \times 0.4}  \sqrt{ \frac{16}{0.04} }

 =  > 25hz

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Answered by MarshmellowGirl
5

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