A 50g bullet is fired from a 10kg gun with a speed of 500m/s. What is the speed of recoiling of gun
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Answer:
2.5m/s
Explanation:
50 gram=0.05 kg
law. of conservation of momentum
m1u1=m2u2
m = mass
m1=0.05kg
m2=10 kg
u1=500m/s
u2=recoil velocity
0.05 x 500 =10 x u2
u2=25/10
u2=2.5m/s
therefore recoil velocity of the gun is 2.5m/s
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