Question

a 50g bullet is fired from a gun of 10kg with speed of recoil of gun​

Answer 1

Answer:

Speed of recoil = 2.5 m/s

Concept:

Apply law of conservation of Linear Momentum. That is, momentum of bullet equals the momentum of gun.

Explanation:

Mass of bullet (mb) = 50g = 0.05Kg

Mass of gun (mg) = 10kg

Let speed of recoil of gun be 'vg'.

Speed of bullet (vb) = 500m/s (average bullet speed)

Applying law of conservation of Linear Momentum,

(mg)(vg) = (mb)(vb)

vg = (0.05*500)/10

vg = 2.5 m/s

Hence, the speed of recoil of gun is 2.5 m/s

Answer 2

Answer:

lets assume speed of bullent is 10m/s

mv=-MV

0.05*10=10V

V=-0.05m/s

speed of gun=0.05 m/s

the negative sign indicates direction of gun is oppo of movement of bullet

:)thank u

Explanation: