A 50kg man is standing at one end of a 25 m long boat. He starts running towards the
other end. On reaching the other end his velocity is 2 ms. If the mass of the boat is
200 kg final velocity of the boat is (in ms)
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Answer:
Let final velocity of boat be v.
So velocity of man with respect to ground is 2+v
As Center-of-mass of system should remain at rest, in absence of external force,
50(2+v)+200v=0⟹v=−
5
2
m/s
negative sign idicates that the velocity of boat is in opposite direction to that of the man.
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