Question

A 50m long train having a constant acceleration crosses a 300m long platform.It leaves the platform at the speed of 50 m/s. What is the acceleration of the train ?
A] 0.6 m/s^2 B] 0.8 m/s^2
C] 3.57 m/s^2
D] 1.2 m/s^2

Answer 1

Answer:

3.57 m/s²

Explanation:

Total displacement covered to completely pass the platform is 300 m + 50 m = 350 m

Use equation of motion

a = (v² - u²)/(2S)

= [(50² - 0²)/(2 × 350)] m/s²

= 3.57 m/s²