Question

A 50m vertical tower casts a 62.3m shadow when the angle of elevation of the sun is 41.6°. The inclination of the ground is?

Answer 1

Answer

Explanation

Given :-

h (height) = 50 m

Shadow distantce = 62.3m

Angle of elevation = 41.6°

Angle B is of 90°

To Find :-

The inclination of the ground

Proof :-

In Δ ABC

AB = Height of tower

BC = Shadow distance

______________________________

We have Formula:

(H)² = (P)² + (B)²

_____________________________

B² = H² - P²

BC² = AC² - AB²

___________________[Put values]

» BC² = 62.3 - 50

» BC² = 12.3

BC = 3.5 m

_____________________________

Angle :-

180° = $\angle \: ABC + \angle \: BAC + \angle \: BCA$

_________[Angle Sum Property]

Put values

180° = 90° + 41.6° + BCA

BCA = 180° - 90° - 41.6°

BCA = 180° - 131.6°

BCA = 48.4°

____________________________

So, the angle is 48.4°

Answer 2

Answer:

73 is inclination............