A 50w television and a 3kw oven are connected to a 300v supply.what is the resistance of each appliance respectively?
Answers
Given : A 50W television and a 3kW oven are connected to a 300v supply.
To find : The resistance of each appliance respectively.
Solution : we know, power consumed by electric appliance , P = V²/R
where V is potential difference applied across appliance and R is resistance of appliance.
case 1 : resistance of television
R = V²/P = (300)²/50 = 1800 Ω
case 2 : resistance of oven
R = V²/P = (300)²/(3000) [ as 3kW = 3000 W]
= 30 Ω
Therefore the resistance of television is 1800 Ω and resistance of oven is 30 Ω.
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