A 51-ft3 tank contains 3 lb of gas at 80°F and a vacuum pressure of 24 in Hg. (a) What is the absolute pressure in psia and psfa? (b) What is the gas’ specific volume and density? (c) What is the temperature in °C, R and K?
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Given:
Volume = 51 ft³
Amount of gas = 3 lb
Temperature = 80 °F
Vacuum pressure = 24Hg
To find:
(a) What is the absolute pressure in psia and psfa?
(b) What is the gas’ specific volume and density?
(c) What is the temperature in °C, R and K?
Solution:
1 inch of mercury = 0.491154 pound per square inch
24 Hg = 24 × 0.491154 psi = 11.788 psi
Absolute pressure in psia = 14.7 - 11.788 = 2.912 psia
Absolute pressure in psfa = 419.328 psfa
Gas specific volume = 51/3 = 17 ft³/lb
density = 1/v = 0.0588 lb/ft³
temp in °C = (80 °F - 32)/1.8 = 26.67 °C
temp in K = 26.67 + 273 = 299.67 K
temp in R = °F + 459.67 = 80 + 459.67 = 539.67 R
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