A 51-kg woman runs up a flight of stairs in 5.0s Her net upward displacement is 5.0 m Approximately, what average power did the woman exert while she was running?
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Answered by
40
Power --> It is the rate of doing work i.e, Power = Work / Time
Given:
mass = 51 kg
time = 5 seconds
displacement = 5 meters
Solution:
Work = F × s
:. F = m × a
F = 51 × 10
= 510 Newton
So, the work done is:
W = 510 × 5
= 2,550 Joules
Now the power : Work/Time
=> 2,550/5
=> 510 Watt
hence, we get the required ans
Hope this helped you dear...
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Answer:
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