Question

A 54 cm long piece of wire is bent into the shape of a semicircular arc bounded by its diameter find its radius.
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Answer 1

Answer:

they given that

semicircular+ diameter= 54

we know that semicircular= circle/2 =2πr/2 = πr

and diameter=2r

so ,

πr+2r=54

r(π+2) = 54

r(22/7+2)= 54

r(22/7+14/7)=54

r(22+14/7)=54

r(36/7)=54

36r/7=54

36r=54×7

36r=387

r=387/36

r=10.5cm