A 54 cm long piece of wire is bent into the space of a semicircular are bounded by its diameter find its radius
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Answered by
3
r(π+2)=54
solve for r and get the answer
solve for r and get the answer
Answered by
9
54cm = Perimeter of semi circle
pi x r + r = 54
22/7 x r + r = 54
2r = 54x7 / 22
2r = 378/ 22
2r = 17.18 cm
r = 8.59 cm
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pi x r + r = 54
22/7 x r + r = 54
2r = 54x7 / 22
2r = 378/ 22
2r = 17.18 cm
r = 8.59 cm
I hope you like it.
Mark it as BRIANLIEST
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