Question

A 55 kg freight truck accelerates from 4.2 m/s to 7.8 m/s in 15 s by applying a constant force. How large of a force is exerted?​

Answer 1

Explanation:

As initial velocity is

4.2

m

s

and final velocity is

7.8

m

s

Initial momentum is

5500

×

4.2

=

23100

k

g

.

m

s

and

final momentum is

5500

×

7.8

=

42900

k

g

.

m

s

∴

Change in momentum is

42900

−

23100

=

19800

k

g

.

m

s