a .55kg basketball moving 6.3m/s to the right collides with a. 06kg tennis ball moving 35m/s to the left . after the collision the tennis ball is moving 39.5 m/s to the right. what is the velocity of the basketball after the collision. assume an elastic collision occurred
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MASS = 0.55 KG (M1)
Velocity = 6.3 m/s (v1)
2nd BAll Velocity = -35 m/s(v2)
2nd BAll Mass = .06 Kg (M2)
MOMENTUM CONSERVATION
M1V1 + M2 V2 = M1 V1# + M2 V2#
KIENATIC ENERGY IS CONSERVED AS THERE IS AN ELASTIC COLLIOSION
Hence M1 VI2 + M2 V2 2 = M1 V1# 2 + M2 V2 # 2
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