A 57m long lane was paved with bricks of the size 20cm*15cm. if the rate of bricks was rupees 2250 per thousand and the bricks worth rupees 89775 were used for paving it, find the width of the lane? please solve it
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let the width of the road be x m
rate of bricks = rs 2250/1000 bricks
total cost = rs 89775
therefore no. of bricks = 89775/2250 * 1000
= 39.9 * 1000
= 39900 bricks used
area of each brick = 20*15 = 300 cm^2
total area of bricks = 39900*300 = 11970000 cm^2
= 1197 m^2
area of road = 1197 = 57*x
x = 1197/57 = 21
therefore width of the road is 21 m
rate of bricks = rs 2250/1000 bricks
total cost = rs 89775
therefore no. of bricks = 89775/2250 * 1000
= 39.9 * 1000
= 39900 bricks used
area of each brick = 20*15 = 300 cm^2
total area of bricks = 39900*300 = 11970000 cm^2
= 1197 m^2
area of road = 1197 = 57*x
x = 1197/57 = 21
therefore width of the road is 21 m
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