Question

a 5cm high object is placed at a distace of 25cm from converging lens of focal length 10cm . determine the nature size and nature of image

Answer 1

I'm not sure of this answer.

Object distance=-25cm

Object height=5cm

Focal length=10cm

1/v - 1/u = 1/f

1/v=3/50

v=50/3 cm.

v/u = image height/object height

Therefore,image height=-2/3 cm.

m=v/u

=50/3 * -1/25

=-0.66

Image nature: real , diminished and inverted.