Question

A 5cm tall object is placed in front of the mirror at a

distance of 30cm. The radius of curvature of the mirror is

40cm. Find the nature, size and position of the image in

such a way that the image is obtained on the screen.​

Answer 1

Answer:

The image formed is real, inverted and has same size as that of the object. The image is formed at a distance of 30 cm from the mirror.

Explanation:

ho = 5 cm

u = - 30 cm

R = 30 cm

f = - 15 cm     ( f = R/2 )

1/v + 1/u = 1/f

1/v =  -1/15 + 1/30

     = - 1/30

v = - 30 cm  (image distance = - 30 cm)

m = -v/u

   = 30 / 30

    = 1  (image is real and inverted)

hi/ho = -v/u

hi/ho = 1

hi = 5 cm