Question

A 5cm tall object placed perpendicular to the principal axis of convex lens of focal length 18cm distance of 12cm from it. Use lens formula to determine the position, size and nature of image formed.

Answer 1

HO = 5cm

f = 18cm

u= -12 cm

by using lens formula,

1/f = 1/v - 1/u

1/18 = 1/v + 1/12

1/18 - 1/12 = 1/v

-1/36 = 1/v

v = -36cm

size of image :::: v/u = hi/ho

-36/-12 = hi / 5

hi= 15 cm

nature ---- virtual , erect, enlarged..

let me know if it's wrong.

bests seldon