Question

A 5kg ball is dropped from the height of 10m.find the K.E just before it reaches.

Answer 1

$total \: p.e \: converts \: into \: kinetic \\ \: energy \: on \: reaching \: the \: ground \\ so \: \: k.e \: = mgh \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 5 \times 9.8 \times 10 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 490 \: j$