Question

a 5kg ball is thrown upwards with
a speed of l0 mls a.find the pe
when it reaches the highest point
b) calculate the max height attained by it
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Answer 1

Answer:

pe at highest point = ke at lowest point

:. pe = 1/2mu² = 1/2*5*100 = 250 J

pe = mgh

250 = 5*10*h

h = 5 m if g = 10 if g is 9.8 then put 9.8 instead of 10