Question

A 5kg ball is thrown upwards with speed of 10m/s. (a) Find P. E when it reaches. highest point.
(b) Calculate maximum height atteuned it
​

Answer 1

Answer:

→ FORMULA = 1/2mv²

→ GIVEN =

→m = 5kg

→ v = 10m/s

Now putting the values :-

(a). 1/2mv² = 1/2(5×(10)²)

→ ANSWER is = 250J

(b). 250J = 5 × 9.8 × h

→ 5.10m

Explanation:

hope this helps you........

plz mark it brainliest......