Question

a 5kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 8 N. opposing the motion. what is the acceleration of the object

Answer 1

Given:

• Mass of block, m = 5 kg
• Action force on block, F₁ = 40 N
• Frictional force (opposing force), F₂ = 8 N

To find:

• Acceleration of block, a =?

Formula required:

• Newton's second law of motion

      F = m a

[ Where F is the net force working on a body of mass m to move it with an acceleration a ]

Solution:

Let, Net force on block be F

then,

→ Net force = (action force on block) - (opposing friction force)

→ F = F₁ - F₂

→ F = 40 - 8

→ F = 32 N

hence, Net force on the block is 32 Newtons.

Now, Using Newtons second law of motion

→ F = m a

→ a = F / m

→ a = 32 / 5

→ a = 6.4  m/s²

Therefore,

• Acceleration of the object would be 6.4 m/s².

Answer 2

Given : A 5kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 8 N. opposing the motion.

　

To find : What is the acceleration of the object.

　

Using formula :

★ Acceleration = Net force/Mass.

　

Calculations :

→ Net force = 40 - 8

→ Net force = 32 N

　

Now applying formula, we get;:

→ Acceleration = 32/5

→ Acceleration = 6.4 m/s²

　

Therefore, 6.4 m/s² is the acceleration of the object.