Question

A 5kg rifle fires a 10g bullet at a velocity of
500 m/s. Find the recoil velocity of the rifle.​

Answer 1

$\huge\mathcal\red{\boxed{\boxed{Answer}}}$

ɢɪᴠᴇɴ

ᴍᴀss ᴏғ ᴛʜᴇ ʀɪғʟᴇ, ᴍ₁ = 5 ᴋɢ

ᴍᴀss ᴏғ ᴛʜᴇ ʙᴜʟʟᴇᴛ, ᴍ₂ = 10 ᴋɢ = 10 × 10⁻³ ᴋɢ

ᴠᴇʟᴏᴄɪᴛʏ ᴏғ ᴛʜᴇ ʙᴜʟʟᴇᴛ, ᴠ₂ = 500 ᴍ/s

ᴛᴏ ᴄᴀʟᴄᴜʟᴀᴛᴇ :-

ᴠᴇʟᴏᴄɪᴛʏ ᴏғ ᴛʜᴇ ʀɪғʟᴇ, ᴠ₁ = ?

ғᴏʀᴍᴜʟᴀ ᴛᴏ ʙᴇ ᴜsᴇᴅ :-

ᴍ₁ᴠ₁ = ᴍ₂ᴠ₂

sᴜʙsᴛɪᴛᴜᴛɪɴɢ ᴀʟʟ ᴛʜᴇ ᴠᴀʟᴜᴇs, ᴡᴇ ɢᴇᴛ

ᴍ₁ᴠ₁ = ᴍ₂ᴠ₂

5 × ᴠ₁ = 10 × 10⁻³ × 500

ᴠ₁ = 10 × 10⁻³ × 500/5

ᴠ₁ = 1 ᴍ/s.

ʜᴇɴᴄᴇ, ᴛʜᴇ ʀᴇᴄᴏɪʟ ᴠᴇʟᴏᴄɪᴛʏ ᴏғ ᴛʜᴇ ʀɪғʟᴇ ɪs 1 ᴍ/s.

Explanation:

Follow me

mark as brainliest

physics expert✨

Answer 2

Given:-

• Mass of bullet is 10g .
• Mass of gun is 5kg.
• Velocity of bullet is 500m/s.

To Find:-

• The recoil velocity of gun .

Formula Used:-

We will make use of concept of law of conservation of momentum.

$\large{\underline{\boxed{\red{\tt{\dag m_1v_1+m_2v_2=m_1u_1+m_2u_2.}}}}}$

Calculation:-

Here as per given data ,

$\tt{ m_1=10g \:and\: m_2=5kg}$

$\tt{v_1=500m/s \:and\:v_2=?}$

$\tt{u_1=u_2=0m/s.}$

On putting the values in power formula stated,

$\tt{\implies m_1u_1+m_2u_2=m_1v_1+m_2v_2 }$

$\tt{\implies 10g\times0+5\times 0=10g\times 500+5kg\times v_2}$

$\tt{\implies 0 = 0.01\times500+5v_2 }$

$\tt{\implies 5v_2=(-5)}$

$\tt{\implies v_2=\dfrac{\cancel{-5}}{\cancel{5}}}$

$\underline{\boxed{\red{\tt{\longmapsto v_2=-1m/s}}}}$

Hence the recoil velocity of gun is -1 m/s.