Question

A 5kg rifle fires a 10g bullet at a velocity of 500 m s find the recoil velocity of the rifle

Answer 1

Answer:

Explanation:

Solution :-

Given :-

Mass of the rifle, m₁ = 5 kg

Mass of the bullet, m₂ = 10 kg = 10 × 10⁻³ kg

Velocity of the bullet, v₂ = 500 m/s

To Calculate :-

Velocity of the rifle, v₁ = ?

Formula to be used :-

m₁v₁ = m₂v₂

Substituting all the values, we get

m₁v₁ = m₂v₂

5 × v₁ = 10 × 10⁻³ × 500

v₁ = 10 × 10⁻³ × 500/5

v₁ = 1 m/s.

Hence, the recoil velocity of the rifle is 1 m/s.

Answer 2

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QUESTION :

A 5kg rifle fires a 10g bullet at a velocity of 500 m s find the recoil velocity of the rifle.

CONCEPT USED :

Conservation of linear momentum.

SOLUTION :

In the above Question, the following information is given...

A 5kg rifle fires a 10g bullet at a velocity of 500 m / s.

Let the recoil Velocity of the gun is v m / s.

Now, according to the concept of Conservation Of Linear Momentum ...

$\rho_{1} = \rho_{2}$

So,

M_{1} × V_{1} = M_{2} × V _{2}

=> 500 = 10 × V_{2}

=> V_{2} = 50 m / s in the opposite direction.