Question

A 5kg shell is fired with a muzzle velocity of 700 m/s from a gun barrel 2.4 m long. calculate the average value of the acceleration

Answer 1

Acceleration of the bullet will be $102083.33m/sec^2$

Explanation:

Mass of the bullet m = 5 kg

Velocity if the bullet v = 700 m /sec

Initial velocity of the bullet u = 0 m/sec ( at rest )

Distance s = 2.4 m

From third equation of motion $v^2=u^2+2as$

So $700^2=0^2+2\times a\times 2.4$

$a=\frac{700^2}{2\times 2.4}=102083.33m/sec^2$

So acceleration of the bullet will be $102083.33m/sec^2$

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