Question

a 5kg wheel is given an acceleration of 10 rads-2 by applied torque of 2Nm calculate its
1. moment of inertia
2.radius of gyration ​

Answer 1

Answer:

1. Moment of inertia of the body is 0.2 kgm^2.

2. Radius of gyration of body is 0.2 m.

Explanation:

Given,

T = 2 Nm

a = 10 rad / s^2

m = 5 kg

By applying the formula of torque

We get,

T = I a

I = T / a

I = 2/10 kgm^2

I = 0.2 kgm^2

Here,

T is the torque of the given body.

I is the moment of inertia of the given body.

a is the angular acceleration of the given body.

m is the mass of the given body.

K is the radius of gyration.

Hence,

Moment of inertia of the body is 0.2 kgm^2.

And

Radius of gyration of body is 0.2 m.