Question

a 5m long and 2 m wide tablecloth includes a border of width 50 cm all around it .find the cost of knitting the border at 10 paise per sq cm​

Answer 1

Answer:

Step-by-step explanation

50cm=0.5 m

length = 5+0.5+0.5=6m

breadth= 2 + 0.5+0.5=3

perimeter of rectangle = 2 (l+b)

                                      = 2 x (6 +3)=18m

18m= 1800cm

10paise =0.10rupees

1800 x 0.10 =180 rupees

Answer 2

Hence the cost of knitting the border at 10 paise per sq cm is 6000 rupees.

Step-by-step explanation:

Given:

Let length L = 5 m = $5 \times 100$ = 500 cm.      [ 1 m = 100 cm]

And breadth = 2 m = $2 \times 100$ = 200 cm.

Area of tablecloth = $Length \times breadth$

                             = $500 \times 200$

                              = $100000 cm^2$

Now width of border = 50 cm

Length of the tablecloth excluding border = (500 - 50 - 50) cm = 400 cm  

Width of tablecloth excluding the border = (200 – 50 – 50) cm = 100 cm

Area of tablecloth excluding the border = $(400\times 100)$

                                                                  = 40000 sq cm.

Area of the border = total area of tablecloth – area of tablecloth excluding the border

                                 = 100000 - 40000

                                 = 60000 sq cm.

Cost of knitting the border at 10 paise per sq cm = $60000 \times 10$

= 600000 paise or 6000 rupees  

Hence the cost of knitting the border at 10 paise per sq cm is 6000 rupees.