Chemistry, asked by advaiths, 1 year ago

a 5M solution of H2so4 is diluted from 1 litre to a volume of 10 liters the normality of the resulting solution will be

Answers

Answered by medhashivani03

normality =n*molarity
n factor of h2so4 is 2
therefore 5*2=10n
10*1=N*10
N=1N

advaiths: can you explain a little more..pls

medhashivani03: look,first of all ,to find normality ,the quantities should be taken into care,we see here 5M is given so we have to find normality of the second solution,in order to do that we have to convert 5M

medhashivani03: into normality first,we know that normality=n factor*molarity

medhashivani03: nfactor=98/49=2

medhashivani03: so Normality=5M*2=10N

medhashivani03: According to formulae=N1V1=N2V2

medhashivani03: SO 10*1L=1OL*N

medhashivani03: N=1N

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